{
 "cells": [
  {
   "cell_type": "markdown",
   "id": "32a44f30",
   "metadata": {},
   "source": [
    "# Listes"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "id": "b368507a",
   "metadata": {},
   "outputs": [],
   "source": [
    "L = [10,47,8,20,30]"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "08e63abe",
   "metadata": {},
   "source": [
    "L est une liste d'entiers. On peut obtenir sa longueur (**len**gth) ainsi :"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "id": "d2b9830d",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "5\n"
     ]
    }
   ],
   "source": [
    "print(len(L))"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "c56ab438",
   "metadata": {},
   "source": [
    "Les éléments de la liste sont numérotés de 0 à len(L)-1 :"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "id": "c806cbb7",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "10\n"
     ]
    }
   ],
   "source": [
    "print(L[0])"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "id": "dab6a08a",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "47\n"
     ]
    }
   ],
   "source": [
    "print(L[1])"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "id": "4fbb9789",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "30\n"
     ]
    }
   ],
   "source": [
    "print(L[4])"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "ce6c3257",
   "metadata": {},
   "source": [
    "## Exercice 1\n",
    "\n",
    "Compléter le programme ci-dessous pour qu'il affiche tous les éléments de la liste L1, un par un :"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "aaddf110",
   "metadata": {},
   "outputs": [],
   "source": [
    "L1 = [5,4,8,9,3,60,4,8,10,11,47,89,23,12]\n",
    "k = 0\n",
    "\n",
    "while k < ... :\n",
    "    print(L1[k])\n",
    "    k = k+1"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "3450af2f",
   "metadata": {},
   "source": [
    "## Exercice 2\n",
    "On peut modifier un des éléments. Par exemple, on peut remplacer ci-dessous 40 par 0 :\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "id": "bf3b80b5",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 5, 1, 0, 80]\n"
     ]
    }
   ],
   "source": [
    "L2 = [1,5,1,40,80]\n",
    "L2[3] = 0\n",
    "print(L2)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "ac69669a",
   "metadata": {},
   "source": [
    "Compléter ci-dessous le programme  qui multiplie tous les éléments de L2 par 10 et affiche la liste finale :"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "1d16b24b",
   "metadata": {
    "scrolled": true
   },
   "outputs": [],
   "source": [
    "for i in range(len(L2)):\n",
    "    ...\n",
    "print(L2)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "ca115c06",
   "metadata": {},
   "source": [
    "## Exercice 3\n",
    "On peut ajouter des élements à la fin d'une liste :"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "id": "76effa56",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[15, 16, 4, 50]\n"
     ]
    }
   ],
   "source": [
    "L = [15,16,4]\n",
    "L = L + [50]\n",
    "print(L)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "86645748",
   "metadata": {},
   "source": [
    "Autre méthode :"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "id": "e6368abd",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[15, 16, 4, 50, 123]\n"
     ]
    }
   ],
   "source": [
    "L.append(123)\n",
    "print(L)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "29acdcf7",
   "metadata": {},
   "source": [
    "Compléter le programme ci-dessous pour obtenir une liste P contenant les entiers de 1 à 100 :"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "5cba67f9",
   "metadata": {},
   "outputs": [],
   "source": [
    "P = []      #commentaire :  [] est une liste vide \n",
    "i = ...\n",
    "\n",
    "while i < ...:\n",
    "    P = P + [...]\n",
    "    ...\n",
    "\n",
    "print(P)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "f5e13384",
   "metadata": {},
   "source": [
    "## Exercice 4\n",
    "Compléter la fonction ci-dessous qui renvoie la liste des N premiers termes de la suite géométrique $(u_n)$ de premier terme $u_0 = 5$ et de raison $0,1$. "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "cdad06b1",
   "metadata": {},
   "outputs": [],
   "source": [
    "def suite(N):\n",
    "    u = []\n",
    "    for k in range(...):\n",
    "        u = u + [...]\n",
    "    return u\n",
    "\n",
    "print(suite(10))    "
   ]
  },
  {
   "cell_type": "markdown",
   "id": "7515c674",
   "metadata": {},
   "source": [
    "## Exercice 5\n",
    "Compléter le programme ci-dessous qui affiche la liste L des termes inférieurs à 200 de la suite $(u_n)$ définie par  $u_0 = 5$ et pour tout entier naturel $n$ par $u_{n+1} = 1,2u_n +7$. \n",
    "\n",
    "NB : pas les 200 premiers termes , mais tous les termes $u_n < 200$ !"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "aa39bf27",
   "metadata": {},
   "outputs": [],
   "source": [
    "u = 5\n",
    "L = []\n",
    "\n",
    "while ..... :\n",
    "    L.append(...)\n",
    "    u = ... \n",
    "    \n",
    "print(L)  "
   ]
  },
  {
   "cell_type": "markdown",
   "id": "ab9ad72f",
   "metadata": {},
   "source": [
    "## Exercice 6\n",
    "Compléter :"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "0f9ffafe",
   "metadata": {},
   "outputs": [],
   "source": [
    "def ps(u,v):\n",
    "    p = ...\n",
    "    for i in range(3):\n",
    "        p = p + u[i]*v[i]\n",
    "    return p\n",
    "\n",
    "a = [1,2,3]\n",
    "b = [-2,-5,4]\n",
    "\n",
    "if ps(a,b) == 0:\n",
    "    print(\"les vecteurs ...............................\")\n",
    "else:\n",
    "    print(\"les vecteurs ...............................\")"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "7659caa2",
   "metadata": {},
   "source": [
    "## Exercice 7\n",
    "Compléter la fonction moyenne qui renvoie la moyenne des notes de la liste N, affectés des coefficients respectifs de la liste C \n",
    "\n",
    "(exemple : la note 16 a pour coefficient 5)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "784ea74d",
   "metadata": {},
   "outputs": [],
   "source": [
    "N = [17,10,16,20,5,11]\n",
    "C = [2,1,5,2,3,4]\n",
    "\n",
    "def moyenne(N,C):\n",
    "    m = 0\n",
    "    s = 0\n",
    "    for k in range(...):\n",
    "        m = m + ...\n",
    "        s = s + ...\n",
    "    return ...\n",
    "\n",
    "print(moyenne(N,C))"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "0e267d24-b029-4172-8e0e-9e2c70d2be82",
   "metadata": {},
   "source": [
    "### Suppléments (?)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "55f5be41-6b76-4d55-8588-bcf11b5dc868",
   "metadata": {},
   "source": [
    "Plus rapide pour l'exercice 1 (k n'est plus un indice mais prend la valeur des éléments de la liste)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 9,
   "id": "25c9750e-0d8f-4502-b4a9-2ec412d3527b",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "5\n",
      "4\n",
      "8\n",
      "9\n",
      "3\n",
      "60\n",
      "4\n",
      "8\n",
      "10\n",
      "11\n",
      "47\n",
      "89\n",
      "23\n",
      "12\n"
     ]
    }
   ],
   "source": [
    "L1 = [5,4,8,9,3,60,4,8,10,11,47,89,23,12]\n",
    "for k in L1:\n",
    "    print(k)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "14ab5aa3-139f-4c28-8e63-78b84e7141c9",
   "metadata": {},
   "source": [
    "### Plus rapide pour l'exercice 3 :"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 10,
   "id": "6665ff99-9b04-481d-bc69-9be3f5823829",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100]\n"
     ]
    }
   ],
   "source": [
    "P = [i for i in range(1,101)]\n",
    "print(P)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "ec62eb44-9c82-4bfb-b8ce-d544eb9c1b06",
   "metadata": {},
   "outputs": [],
   "source": []
  }
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