{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Listes" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "L = [10,47,8,20,30]" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "C'est une liste d'entiers. On peut obtenir sa longueur ainsi :" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "len(L)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Pour obtenir un des éléments de la liste :" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "L[0]" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "L[1]" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "L[4]" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Exercice 1\n", "Compléter le programme ci-dessous pour qu'il affiche tous les éléments de la liste L1 :" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "L1 = [5,4,8,9,3,60,4,8,10,11,47,89,23,12]\n", "k = 0\n", "\n", "while k < ... :\n", " print(L1[k])\n", " k = k+1" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Exercice 2\n", "On peut modifier un des éléments. Par exemple, on peut remplacer ci-dessous 40 par 0 :\n" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "L2 = [1,5,1,40,80]\n", "L2[3] = 0\n", "print(L2)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Ecrire ci-dessous un programme qui multiplie tous les éléments de L2 par 10 :" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Exercice 3\n", "On peut ajouter des élements à la fin d'une liste :" ] }, { "cell_type": "code", "execution_count": 2, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "[15, 16, 4, 50]\n" ] } ], "source": [ "L = [15,16,4]\n", "L = L + [50]\n", "print(L)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Compléter le programme ci-dessous pour obtenir une liste contenant les entiers de 1 à 100 :" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "L = [1]\n", "i = ...\n", "\n", "while i < ...:\n", " L = L + [...]\n", " \n", "print(L)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Exercice 4\n", "A quoi sert le programme ci-dessous ?" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "L3 = [1,3,5,7,8,9,11,13,15]\n", "k = 0\n", "S = 0\n", "\n", "while k < len(L3):\n", " S = S + L3[k]\n", " k = k+1\n", "print(S)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Exercice 5\n", "L4 est la liste des nombres premiers inférieurs à 100. Calculer leur somme. " ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "L4 = [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97]\n", "\n", "\n" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [] } ], "metadata": { "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.7.3" } }, "nbformat": 4, "nbformat_minor": 2 }