{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Second degré"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "But : \n",
    "*  entrer $a$, $b$ , et $c$\n",
    "* afficher les solutions éventuelles de $ax^2 + bx +c =0$"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Résolution de ax^2 + bx +c = 0\n",
      "Delta =  -31\n",
      "L'équation n'admet pas de solution.\n"
     ]
    }
   ],
   "source": [
    "from math import sqrt\n",
    "\n",
    "a = 1\n",
    "b = 3\n",
    "c = 10\n",
    "\n",
    "print('Résolution de ax^2 + bx +c = 0')\n",
    "          \n",
    "delta = b**2 - 4*a*c\n",
    "print('Delta = ' , delta)\n",
    "\n",
    "if delta > 0:\n",
    "    print(\"L'équation admet deux solutions : \", (-b-sqrt(delta))/(2*a), \" et \", (-b+sqrt(delta))/(2*a) )\n",
    "else:\n",
    "    if delta == 0:\n",
    "        print(\"L'équation admet une solution : \", -b/(2*a) )\n",
    "    else:\n",
    "        print(\"L'équation n'admet pas de solution.\")\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "Deuxième version où $a$, $b$ et $c$ sont demandés à l'utilisateur (et pas entrés par le programmeur dans le programme)'"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Résolution de ax^2 + bx +c = 0\n",
      "Saisir a\n",
      "1\n",
      "Saisir b\n",
      "3\n",
      "Saisir c\n",
      "-4\n",
      "Delta =  25.0\n",
      "L'équation admet deux solutions :  -4.0  et  1.0\n"
     ]
    }
   ],
   "source": [
    "from math import sqrt\n",
    "\n",
    "print('Résolution de ax^2 + bx +c = 0')\n",
    "a = float(input('Saisir a\\n'))\n",
    "b = float(input('Saisir b\\n'))\n",
    "c = float(input('Saisir c\\n'))\n",
    "          \n",
    "delta = b**2 - 4*a*c\n",
    "print('Delta = ' , delta)\n",
    "\n",
    "if delta > 0:\n",
    "    print(\"L'équation admet deux solutions : \", (-b-sqrt(delta))/(2*a), \" et \", (-b+sqrt(delta))/(2*a) )\n",
    "else:\n",
    "    if delta == 0:\n",
    "        print(\"L'équation admet une solution : \", -b/(2*a) )\n",
    "    else:\n",
    "        print(\"L'équation n'admet pas de solution.\")\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": []
  }
 ],
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  "kernelspec": {
   "display_name": "Python 3",
   "language": "python",
   "name": "python3"
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  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 3
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython3",
   "version": "3.6.1"
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